Calculates the frequency table with respect to the open right boundary convention for a discrete data set.
[Visual Basic]
Overloads Public Shared Function FrequencyTableOR( _
ByVal s As Series, _
ByVal boundaries() As Double _
) As Series[C#]
public static Series FrequencyTableOR(
Series s,
double [] boundaries
);
Say for example the boundary points used are {b_1, b_2, ..., b_n}, now the
first term of the array returned which represents the frequency table, is the number of elements
from the data set within the interval (-infinity, b_1), the second term of the array
returned is the number of elements from the data set within the interval [b_1, b_2),
and so on...
Consider the set of boundaries { 1, 2, 3, 4, 5 }, which divide the real
line into six sub-intervals. Now if we use the open right boundary convention then the
real line will be divided into the sub-intervals:
(-infinity, 1), [1, 2), [2, 3), [3, 4), [4, 5), [5, infinity)
Note that, each point on the real line can be assigned to one of these sub-intervals
and therefore when assigning a data point to one of these intervals there will only
be one sub-interval in which it belongs.
Therefore, if we consider the data set { 0.5, 1.4, 1.3, 2.0, 2.3, 4.5, 5.5},
if you assign this data set in accordance with the above the conventions then we will
have using Open Right Boundary (ORB) convention:
(-infinity, 1], we assign the data element 0.5;
and hence the frequency of this interval is 1.
[1, 2), we assign the data element 1.4, 1.3;
and hence the frequency of this interval (wrt ORB convention) is 2.
[2, 3), we assign the data element 2.0, 2.3;
and hence the frequency of this interval (wrt ORB convention) is 2.
[3, 4), we assign no data elements, and hence the frequency
of this interval (wrt ORB convention) is 0.
[4, 5), we assign the data element 4.5,
and hence the frequency of this interval (wrt ORB convention) is 1.
[5, infinity), we assign the data element 5.5,
and hence the frequency of this interval (wrt ORB convention) is 1.
Hence, in this case the series returned corresponding to the frequency table will be
{1, 2, 2, 0, 1, 1}.
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